60x^2-35x-50=0

Solution for 60x^2-35x-50=0 equation:

60x^2-35x-50=0

a = 60; b = -35; c = -50;
Δ = b2-4ac
Δ = -352-4·60·(-50)
Δ = 13225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{13225}=115$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-115}{2*60}=\frac{-80}{120}
=-2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+115}{2*60}=\frac{150}{120}
=1+1/4
$